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RSA Algorithm
//RSA ALGORITHM
#include <stdio.h>
int modulo(int e, int n, int pt)
{
int h;
if(e==0)
return 1;
else if(e==1)
return pt%n;
else
{
h = modulo(e/2, n, pt);
if(e%2==0)
return ((h*h)%n)%n;
else
return ((h*h)*(pt%n))%n;
}
}
int main()
{
int p, q, n, z, e, d, pt,ct;
printf("Enter p & q values <prime numbers>: ");
scanf("%d%d", &p, &q);
n = p*q;
z = (p-1)*(q-1);
printf("\nEnter a relative prime number to %d i.e., e value: ",z);
scanf("%d", &e);
d = 1;
while((d*e)%z!=1)
d++;
printf("d value is: %d\n", d);
printf("Keys are: <e, n>:(%d, %d)\t<d, n>:(%d, %d)",e,n,d,n);
printf("\n\nEnter message<pt> such that pt < %d : ",n);
scanf("%d", &pt);
ct = modulo(e,n,pt);
printf("\nCipher Text: %d\n",ct);
pt = modulo(d,n,ct);
printf("Decrypted Text: %d",pt);
return 0;
}
/* SAMPLE OUTPUT
Enter p & q values <prime numbers>: 11 7
Enter a relative prime number to 60 i.e., e value: 13
d value is: 37
Keys are: <e, n>:(13, 77) <d, n>:(37, 77)
Enter message<pt> such that pt < 77 : 5
Cipher Text: 26
Decrypted Text: 5
*/ Dijkstra's Algorithm
/PROGRAM FOR DIJKSTRA'S ALGORITHM #include <stdio.h> #include <conio.h> #define GRAPHSIZE 2048 #define INFINITY GRAPHSIZE*GRAPHSIZE #define MAX(a, b) ((a > b) ? (a) : (b)) int e; /* The number of nonzero edges in the graph */ int n; /* The number of nodes in the graph */ long dist[GRAPHSIZE][GRAPHSIZE]; /* dist[i][j] is the distance between node i and j; or 0 if there is no direct connection */ long d[GRAPHSIZE]; /* d[i] is the length of the shortest path between the source (s) and node i */ int prev[GRAPHSIZE]; /* prev[i] is the node that comes right before i in the shortest path from the source to i*/ void printD() { int i; printf("Distances:\n"); for (i = 1; i <= n; ++i) printf("%d\t", i); printf("\n"); for (i = 1; i <= n; ++i) { printf("%ld\t", d[i]); } printf("\n"); } /* Prints the shortest path from the source to dest. * dijkstra(int) MUST be run at least once BEFORE this is called */ void printPath(int dest) { if (prev[dest] != -1) printPath(prev[dest]); printf("%d ", dest); } void dijkstra(int s) { int i, k, mini; int visited[GRAPHSIZE]; for (i = 1; i <= n; ++i) { d[i] = INFINITY; prev[i] = -1; /* no path has yet been found to i */ visited[i] = 0; /* the i-th element has not yet been visited */ } d[s] = 0; for (k = 1; k <= n; ++k) { mini = -1; for (i = 1; i <= n; ++i) if (!visited[i] && ((mini == -1) || (d[i] < d[mini]))) mini = i; visited[mini] = 1; for (i = 1; i <= n; ++i) if (dist[mini][i]) if (d[mini] + dist[mini][i] < d[i]) { d[i] = d[mini] + dist[mini][i]; prev[i] = mini; } } } void main() { int i, j; int u, v, w; //clrscr(); FILE *fin = fopen("dist.txt", "r"); fscanf(fin, "%d", &e); for (i = 0; i < e; ++i) for (j = 0; j < e; ++j) dist[i][j] = 0; n = -1; for (i = 0; i < e; ++i) { fscanf(fin, "%d%d%d", &u, &v, &w); dist[u][v] = w; n = MAX(u, MAX(v, n)); } fclose(fin); dijkstra(1); printD(); printf("\n"); for (i = 1; i <= n; ++i) { printf("Path to %d: ", i); printPath(i); printf("\n"); } getch(); } /*SAMPLE OUTPUT ____________________ inputfile: dist.txt 10 1 2 10 1 4 5 2 3 1 2 4 3 3 5 6 4 2 2 4 3 9 4 5 2 5 1 7 5 3 4 _____________________
OUTPUT
Distances:
1 2 3 4 5
0 7 8 5 7
Path to 1: 1
Path to 2: 1 4 2
Path to 3: 1 4 2 3
Path to 4: 1 4
Path to 5: 1 4 5
*/ Distance Vector Routing Algorithm
//PROGRAM FOR DISTANCE VECTOR ROUTING ALGORITHM
#include<stdio.h>
#include<conio.h>
struct node
{
unsigned dist[20];
unsigned from[20];
}rt[10];
int main()
{
int dmat[20][20];
int n,i,j,k,count=0;
printf("\nEnter number of nodes : ");
scanf("%d",&n);
printf("\nEnter the cost matrix :\n");
for(i=0;i<n;i++)
for(j=0;j<n;j++)
{
scanf("%d",&dmat[i][j]);
dmat[i][i]=0;
rt[i].dist[j]=dmat[i][j];
rt[i].from[j]=j;
}
do
{
count=0;
for(i=0;i<n;i++)
for(j=0;j<n;j++)
for(k=0;k<n;k++)
if(rt[i].dist[j]>dmat[i][k]+rt[k].dist[j])
{
rt[i].dist[j]=rt[i].dist[k]+rt[k].dist[j];
rt[i].from[j]=k;
count++;
}
}while(count!=0);
for(i=0;i<n;i++)
{
printf("\n\nNODE %d ROUTING TABLE",i+1);
printf("\nNode\tDistance\tViaNode\n");
for(j=0;j<n;j++)
{
printf("\t\n %d\t %d\t\t %d",j+1,rt[i].dist[j],rt[i].from[j]+1);
}
}
printf("\n\n");
return 0;
getch();
}
/*SAMPLE OUTPUT
**********INPUT*********
Enter number of nodes : 5
Enter the cost matrix :
0 4 2 6 99
4 0 99 99 99
2 99 0 3 99
6 99 3 0 2
99 99 99 2 0
::::::OUTPUT ::::: NODE 1 ROUTING TABLE
Node Distance ViaNode
1 0 1
2 4 2
3 2 3
4 5 3
5 7 4
NODE 2 ROUTING TABLE
Node Distance ViaNode
1 4 1
2 0 2
3 6 1
4 9 1
5 11 1
NODE 3 ROUTING TABLE
Node Distance ViaNode
1 2 1
2 6 1
3 0 3
4 3 4
5 5 4
NODE 4 ROUTING TABLE
Node Distance ViaNode
1 5 3
2 9 1
3 3 3
4 0 4
5 2 5
NODE 5 ROUTING TABLE
Node Distance ViaNode
1 7 4
2 11 4
3 5 4
4 2 4
5 0 5
Cyclic Redundancy Check
=> A Generator is shared between the Sender and the Receiver.
=> Sender will convert Dataword into Codeword using the Generator and send it
to the Receiver.
=> Receiver upon receiving the Codeword, will check for errors in the received
Codeword with the help of the Generator.
=> If no error is found, receiver can extract Dataword from the Codeword.
Sender Side:
Generator/Divisor: 1100000001011 (Total 13-bits)
Dataword: 10101 (5-bits)
Extended Dataword: 10101000000000000 (17-bits: Dataword + 12 0's)
1100000001011 ) 10101000000000000 ( 11001
1100000001011
_____________
x1101000010110
1100000001011
_____________
x0010000111010
0000000000000
_____________
x0100001110100
0000000000000
_____________
x1000011101000
1100000001011
_____________
x100011100011
=> So, CRC Bits are: 100011100011
=> Now Codeword is 10101100001110100 (17-bits: Dataword + CRC bits)
=> Sender will send this Codeword to the Receiver.
Receiver Side:
Codeword: 10101100011100011
Generator/Divisor: 1100000001011
1100000001011) 10101100011100011 ( 11001
1100000001011
_____________
x1101100001010
1100000001011
_____________
x0011000000010
0000000000000
_____________
x0110000000101
0000000000000
_____________
x1100000001011
1100000001011
_____________
0000000000000
=> Reached Codeword contain no errors and now extract Dataword from Codeword
=> Dataword is 10101 [[by removing (Generator_Size - 1) bits from Codeword from Right]]
// PROGRAM FOR CYCLIC REDUNDANCY CHECK
#include<stdio.h>
int main()
{
int ds, dws, i, j, k, c=0; // ds-DivisorSize: dws-DataWordSize:
int div[100], dw[100], ta[100]; // div-Divisor: dw-DataWord: ta-TemporaryArray
//TAKING INPUT - DIVISOR
printf("Enter the size of divisor: ");
scanf("%d", &ds);
printf("Enter the divisor in bit pattern: ");
for(i=0; i<ds ; i++)
scanf("%d", &div[i]);
//TAKING INPUT - DATAWORD
printf("Enter the size of the DataWord: ");
scanf("%d",&dws);
printf("Enter the DATAWORD in bit pattern: ");
for(i=0; i<dws; i++)
scanf("%d",&dw[i]);
//ADDING ZEROS TO THE DATAWORD i.e., WE GOT EXTENDED DATAWORD HERE
for(i=dws; i<(dws+ds-1); i++)
dw[i] = 0;
//PRINTING THE EXTENDED DATAWORD
printf("Data after inserting zeros or <EXTENDED DATAWORD> : ");
for(i=0; i<(dws+ds-1); i++)
printf("%d", dw[i]);
//COPYING DATAWORD INTO TEMPORARY ARRAY
for(i=0; i<(dws+ds-1); i++)
ta[i] = dw[i];
//GENERATING THE REDUNDANT BITS
for(i=0; i!= dws; i++)
{
if(ta[i]==1)
for(j=0, k=i; j<ds; j++, k++)
ta[k] = ta[k]^div[j];
}
//ADDING REDUNDANT BITS TO THE DATAWORD
for(i=dws; i<(dws+ds-1); i++)
dw[i] = ta[i];
//PRINTING THE CODEWORD
printf("\n\nThe Generated CODEWORD is: ");
for(i=0; i<(dws+ds-1); i++)
printf("%d", dw[i]);
//COPYING CODEWORD INTO TEMPORARY ARRAY
for(i=0; i<(dws+ds-1); i++)
ta[i] = dw[i];
//DIVIDING CODEWORD WITH DIVISOR AT RECEIVERS END
for(i=0; i!= dws; i++)
{
if(ta[i]==1)
for(j=0, k=i; j<ds; j++, k++)
ta[k] = ta[k]^div[j];
}
printf("\nThe Remainder @ receiver's End is: ");
for(i=dws; i<(dws+ds-1); i++)
printf("%d",ta[i]);
//CHECKING IF THERE ARE ANY 1s IN THE REMAINDER
for(i=dws; i<(dws+ds-1); i++)
{
if(ta[i]!=0)
c++;
}
if(c==0)
printf("\nThe Codeword hasn't been altered::Message sent SUCCESSFULLY :)");
else
printf("\nThe Codeword has been altered :(");
return 0;
}
/* EXAMPLE OUTPUT
Enter the size of divisor: 4
Enter the divisor in bit pattern: 1 0 1 1
Enter the size of the DataWord: 5
Enter the DataWord in bit pattern: 1 0 1 1 1
Data after inserting zeros or <EXTENDED DATAWORD> : 10111000
The Generated CODEWORD is: 10111011
The Remainder @ receiver's End is: 000
The Codeword hasn't been altered::Message sent SUCCESSFULLY :)
*/
Character Stuffing
// PROGRAM FOR CHARACTER STUFFING
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
{
int i,j=1;
char str1[100], str2[100], str3[100];
//clrscr();
printf("Enter a string: ");
scanf("%s",&str1);
//GENERATING ENCODED MESSAGE
str2[0] = '@';
for(i=0; i< strlen(str1); i++)
{
if( str1[i]=='@' || str1[i] == '#')
{
str2[j] = '#'; j++;
}
str2[j] = str1[i]; j++;
}
str2[j] = '@'; j++;
str2[j] = '\0';
printf("Encoded message is: %s", str2);
// DECODED MESSAGE or ACTUAL MESSAGE
j=0;
for(i=1; i<(strlen(str2)-1);i++)
{
if(str2[i]=='#')
i++;
str3[j]=str2[i];
j++;
}
str3[j] ='\0';
printf("\nDecoded or actual message is: %s", str3);
getch();
} Bit Stuffing
//PROGRAM FOR BIT-STUFFING #include<stdio.h> #include <string.h> int main() { char ed[100]; //ed - Entered Data char ta[100]; //ta - Temporary Array char dd[100]; //dd - Decoded Data char ecd[100]={'0','1','1','1','1','1','1','0'}; //ecd - EnCoded Data int n, i, j=0, count=0; printf("Enter the string:"); scanf("%s",&ed); printf("\nEntered bit pattern: %s",ed); //ENCODING for(i=0; i<strlen(ed); i++) { if(ed[i]=='1') count++; else count = 0; ta[j]=ed[i]; j++; if(count==5) { ta[j] = '0'; j++; count = 0; } } ta[j] = '\0'; strcat(ta,ecd); strcat(ecd,ta); printf("\nEncoded Data: %s",ecd); //DECODING j=0; count =0; for(i=8; i<strlen(ecd)-8; i++) { if(ecd[i]=='1') count ++; else count = 0; dd[j] = ecd[i]; j++; if(count==5) { i++; count=0; } } dd[j] ='\0'; printf("\nDecoded Data: %s", dd); return 0; }
Optimal Page Replacement Algorithm
//OPTIMAL PAGE REPLACEMENT ALGORITHM
#include <stdio.h>
#include <conio.h>
int main()
{
int n, rss, fa[20], rsa[50], ta[20]; //n-No_of_Frames
//rss->Reference_String_Size::fa->Frame_Array
//rsa->Reference_String_Array::ta->Temporary_Array
int i,j,k, d,pfc=0,npf, cp,ff=0;
//d-distance[How soon a page will be used again?]
//cp->Current_Position :: ff->Frames_Filled ::pfc->Page_Fault_Count
//npf:NO_Page_Faults [0-False, 1-True]
printf("Enter number of frames: ");
scanf("%d", &n);
printf("Enter number of pages in reference string: ");
scanf("%d", &rss);
printf("Enter Reference string:\n");
for(i=0; i<rss; i++)
scanf("%d",&rsa[i]);
for(i=0;i<n;i++)
{
fa[i]=-1;
ta[i]=999;
}
printf("\nCURRENT_PAGE\t\tPAGES_IN_FRAME\t\tPAGE_FAULT_OCCURED?\n");
for(i=0; i<rss; i++)
{
printf("\n\t%d\t\t",rsa[i]);
npf=0;
for(j=0;j<n;j++) //Checking for the page in FRAME ARRAY
{
if(fa[j]==rsa[i])
{
npf = 1;
printf("\t\t\t\tNO");
break;
}
}
if(npf==0) // if page fault occurs
{
pfc++;
if(ff<n)
{
fa[ff]=rsa[i];
ff++;
}
else
{
for(k=0;k<n;k++)
ta[k]=999;
for(k=0; k<n; k++) //finding how near a page is
{
d = 0; // d-> distance
for(j=i+1;j<rss;j++)
{
if(fa[k]==rsa[j])
{
ta[k]=d;
break;
}
else
d++;
}
}
cp=0;
for(j=1;j<n;j++)
{
if(ta[cp]<ta[j])
cp=j; //cp->current position
}
fa[cp] = rsa[i];
}
for(j=0;j<n;j++)
printf("%d\t",fa[j]);
printf("\tYES");
}
}
printf("\nTotal no of pagefaults: %d",pfc);
return 0;
} LRU Page Replacement Algorithm
//LRU PAGE REPLACEMENT ALGORITHM
#include <stdio.h>
#include <conio.h>
int main()
{
int n, rss, fa[20], rsa[50], ta[20]; //n-No_of_Frames
//rss->Reference_String_Size::fa->Frame_Array
//rsa->Reference_String_Array::ta->Temporary_Array
int i,j,k,pfc=0,npf, cp;
//cp->Current_Position ::pfc->Page_Fault_Count
//npf:NO_Page_Faults [0-False, 1-True]
printf("Enter number of frames: ");
scanf("%d", &n);
printf("Enter number of pages in reference string: ");
scanf("%d", &rss);
printf("Enter Reference string:\n");
for(i=0; i<rss; i++)
scanf("%d",&rsa[i]);
for(i=0;i<n;i++)
fa[i]=-1;
for(i=0;i<n;i++)
ta[i]=n-(i+1);
printf("\nCURRENT_PAGE\t\tPAGES_IN_FRAME\t\tPAGE_FAULT_OCCURED?\n");
for(i=0; i<rss; i++)
{
printf("\n\t%d\t\t",rsa[i]);
npf=0;
for(j=0;j<n;j++) //Checking for the page in FRAME ARRAY
{
if(fa[j]==rsa[i])
{
npf = 1;
for(k=0;k<n;k++)
ta[k]++;
ta[j]=0;
printf("\t\t\t\tNO");
break;
}
}
if(npf==0) // if page fault occurs
{
pfc++;
cp=0;
for(j=1;j<n;j++)
if(ta[cp]<ta[j])
cp=j; //cp->current position
fa[cp] = rsa[i];
for(k=0;k<n;k++)
ta[k]++;
ta[cp]=0;
for(j=0;j<n;j++)
printf("%d\t",fa[j]);
printf("\tYES");
}
}
printf("\nTotal no of pagefaults: %d",pfc);
return 0;
} FIFO Page Replacement Algorithm
//FIFO PAGE REPLACEMENT ALGORITHM
#include <stdio.h>
#include <conio.h>
int main()
{
int n, rss, fa[20], rsa[50]; //n-No_of_Frames
//rss->Reference_String_Size::fa->Frame_Array
//rsa->Reference_String_Array::ta->Temporary_Array
int i,j,k,pfc=0,npf, cp=0;
//cp->Current_Position :: ff->Frames_Filled ::pfc->Page_Fault_Count
//npf:NO_Page_Faults [0-False, 1-True]
printf("Enter number of frames: ");
scanf("%d", &n);
printf("Enter number of pages in reference string: ");
scanf("%d", &rss);
printf("Enter Reference string:\n");
for(i=0; i<rss; i++)
scanf("%d",&rsa[i]);
for(i=0;i<n;i++)
fa[i]=-1;
printf("\nCURRENT_PAGE\t\tPAGES_IN_FRAME\t\tPAGE_FAULT_OCCURED?\n");
for(i=0; i<rss; i++)
{
printf("\n\t%d\t\t",rsa[i]);
npf=0;
for(j=0;j<n;j++) //Checking for the page in FRAME ARRAY
{
if(fa[j]==rsa[i])
{
npf = 1;
printf("\t\t\t\tNO");
break;
}
}
if(npf==0) // if page fault occurs
{
pfc++;
fa[cp] = rsa[i];
cp=(cp+1)%n;
for(j=0;j<n;j++)
printf("%d\t",fa[j]);
printf("\tYES");
}
}
printf("\nTotal no of pagefaults: %d",pfc);
return 0;
} Priority Scheduling
//PROGRAM FOR PRIORITY CPU SCHEDULING ALGORITHM" WITH NO-PRE_EMPTION & ARRIVAL TIMES
#include<stdio.h>
#include<string.h>
int main(void)
{
//VARIABLE DECLARATION
char pn[20][20], c[20][20]; //PN-PROGRAM NAMES C-A TEMPORARY ARRAY
int n,i,j,at[20], bt[20], pt[20], wt[20],ct[20],tat[20];
//bt-BURST TIME ;pt-PRIORITY;wt-WAITING TIME; tat-TURN AROUND TIME
int temp1, temp2, temp3, count=0,twt=0;//,tat=0;
printf("Enter number of processes:");
scanf("%d", &n);
printf("Enter <ProcessName> <ArrivalTime> <BurstTime> <Priority> :\n");
//TAKING INPUT VALUES i.e., PROCESS-NAMES, ARRIVAL-TIMES AND BURST-TIMES
for(i=0; i<n; i++)
scanf("%s%d%d%d",&pn[i],&at[i],&bt[i],&pt[i]);
//SCHEDULING THE PROCESSES ACCORDING TO SJF
for(i=0 ; i<n; i++)
{
for(j=i+1; j<n; j++)
if (
//IF THERE IS NO PROCESS IN MAIN MEMORY,
//SORT PROCESSES ACCORDING TO ARRIVAL TIMES &
//IF WE GOT PROCESSES WITH SAME ARRIVAL TIME SORT THEM BY PRIORITY
( (i==0||count<1)&&(at[i]>at[j]||(at[i]==at[j]&&pt[i]>pt[j])) )
//IF WE GOT ONLY ONE PROCESS IN MAIN MEMORY AFTER COMPLETION OF THE CURRENT PROCESS
|| (count == 1 && ct[i-1]>=at[j])
//IF WE GOT MORE THAN ONE PROCESS IN MAIN MEMORY, SORT THEM BY PRIORITY
|| ((ct[i-1]>=at[j]&&pt[i]>pt[j]))// || (ct[i-1]<at[i]&&ct[i-1]>=at[j]))
)
//SWAPPING PROCESSES
{
temp1 = bt[i];
bt[i] = bt[j];
bt[j] = temp1;
temp2 = at[i];
at[i] = at[j];
at[j] = temp2;
temp3 = pt[i];
pt[i] = pt[j];
pt[j] = temp3;
strcpy(c[i],pn[i]);
strcpy(pn[i],pn[j]);
strcpy(pn[j],c[i]);
}
if(i==0 || count<1)
ct[i] = at[i] + bt[i];
else
ct[i] = ct[i-1] + bt[i];
wt[i] = ct[i] - (at[i] + bt[i]);
tat[i] = ct[i] - at[i];
count = 0 ;
for(j=i+1; j<n; j++)
if(ct[i]>=at[j])
count++;
}
//PRINTING THE VALUES AFTER ALL PREOCESSES COMPLETED
printf("S.N.\tPN\tAT\tBT\tPri\tCT\tWT\tTAT\n");
for(i=0; i<n; i++)
printf("%d\t%s\t%d\t%d\t%d\t%d\t%d\t%d\n",(i+1),pn[i],at[i],bt[i],pt[i],ct[i],wt[i],tat[i]);
} //END OF MAIN
/* EXAMPLE OUTPUT
Enter number of processes:4
Enter <ProcessName> <ArrivalTime> <BurstTime> <Priority> :
p1 3 2 4
p2 2 1 6
p3 10 2 3
p4 2 3 2
S.N. PN AT BT Pri CT WT TAT
1 p4 2 3 2 5 0 3
2 p1 3 2 4 7 2 4
3 p2 2 1 6 8 5 6
4 p3 10 2 3 12 0 2
*/ Round Robin CPU Scheduling Algorithm
//PROGRAM FOR ROUND ROBIN "CPU SCHEDULING ALGORITHM" WITH ARRIVAL TIMES
#include<stdio.h>
#include<string.h>
int main(void)
{
//VARIABLE DECLARATION
char pn[20][20], c[20][20]; //PN-PROGRAM NAMES
int n,i,j,k,l, tq, at[20], bt[20], rbt[20], wt[20],tt[20],ct[20]; //bt-BURST TIME ; wt-WAITING TIME; tat-TURN AROUND TIME
int temp1, temp2, temp3, count=0,twt=0, tn;//,tat=0;
printf("Enter <Number_of_Processes & Time_Quantum:\n");
scanf("%d%d", &n, &tq);
printf("Enter PN, AT, BT:\n");
//TAKING INPUT VALUES i.e., PROCESS-NAMES, ARRIVAL-TIMES, BURST-TIMES
for(i=0; i<n; i++)
scanf("%s%d%d",&pn[i],&at[i],&bt[i]);
for(i=0; i<n; i++)
rbt[i]=bt[i];
//SCHEDULING THE PROCESSES ACCORDING TO SJF
for(i=0;i<n;i++)
{
for(j=i+1; j<n;j++)
{
//SORTING BASED ON ARRIVAL TIMES
if(at[i]>at[j])
{
temp1 = bt[i];
bt[i] = bt[j];
bt[j] = temp1;
temp2 = at[i];
at[i] = at[j];
at[j] = temp2;
temp3 = rbt[i];
rbt[i] = rbt[j];
rbt[j] = temp3;
strcpy(c[i],pn[i]);
strcpy(pn[i],pn[j]);
strcpy(pn[j],c[i]);
}
} //END OF J FOR-LOOP
}//END OF I FOR-LOOP
tn = at[0];
label:
for(i=0; i<n; i++)
{
if(at[i]>tn) i--;
if(rbt[i]>0)
{
if(rbt[i]>tq)
{
tn += tq;
rbt[i] -= tq;
}
else
{
tn += rbt[i];
rbt[i] = 0;
ct[i] = tn;
count++;
}
}
}
if(count<n) goto label;
//CALCULATING WAITING TIME & TAT
for(i=0;i<n;i++)
{
wt[i] = ct[i]-at[i]-bt[i];
twt += wt[i];
}
//PRINTING THE VALUES AFTER ALL PREOCESSES COMPLETED
printf("S.N.\tPN\tAT\tBT\tCT\tWT\n");
for(i=0; i<n; i++)
printf("%d\t%s\t%d\t%d\t%d\t%d\n",(i+1),pn[i],at[i],bt[i],ct[i],wt[i]);
printf("Total waiting time:%d", twt);
} //END OF MAIN SJF CPU Scheduling Algorithm (Preemptive)
//PROGRAM FOR SHORTEST-JOB-FIRST(SJF) "CPU SCHEDULING ALGORITHM" WITH PRE_EMPTION
#include<stdio.h>
#include<conio.h>
int main()
{
int n,at[10], bt[10], ct[10], wt[10], tn =0, c, ta[10],tat[10];
//at-ArritvalTime::br-BurstTime::ct-CompletionTime::ta-TemporaryArray
//wt-WaitingTime::tat-TurnAroundTime::tn-CurrentTime(TimeNow)
// int i, j, k, tot, pc=0, pointer = 0, lp=-1;//lp-Last-executedProcess
int i, k, tot, pc=0, pointer = 0, lp=-1;//lp-Last-executedProcess
char pn[10][10];
printf("Enter the number of processes: ");
scanf("%d",&n);
printf("Enter <ProcessName> <ArrivalTime> <BurstTime>\n");
for(i=0;i<n;i++)
scanf("%s%d%d",&pn[i],&at[i],&bt[i]);
for(i=0; i<n; i++)
{
ct[i] = -1;
ta[i] = bt[i];
}
while(pc!=n)
{
k=0;
c = 0;
for(i=0; i<n; i++)
{
if(ct[i]<0 && at[i]<=tn)
c++;
}
if(c==0)
tn++;
else
{
pointer = 0;
while(at[pointer]>tn || ct[pointer]>0)
pointer++;
for(k=pointer+1; k<n; k++)
if( (at[k]<=tn && ct[k]<0) &&
( (bt[pointer]==bt[k] && k==lp) || bt[pointer]>bt[k] ) )
pointer = k;
if(ct[pointer]<0)
{
bt[pointer]--;
tn++;
if(bt[pointer]==0)
{
ct[pointer] = tn;
wt[pointer] = ct[pointer] - ( at[pointer]+ ta[pointer] );
tat[pointer] = ct[pointer] - at[pointer];
pc++;
}
}
lp = pointer;
}
}
printf("\nPN\tAT\tBT\tCT\tWT\tTAT\n");
for(i=0;i<n;i++)
printf("%s\t%d\t%d\t%d\t%d\t%d\n",pn[i],at[i],ta[i],ct[i],wt[i],tat[i]);
return 0;
}
/* SAMPLE OUTPUT
Enter the number of processes: 6
Enter <ProcessName> <ArrivalTime> <BurstTime>
p1 3 1
p2 1 4
p3 10 6
p4 25 10
p5 1 3
p6 12 3
PN AT BT CT WT TAT
p1 3 1 5 1 2
p2 1 4 9 4 8
p3 10 6 19 3 9
p4 25 10 35 0 10
p5 1 3 4 0 3
p6 12 3 15 0 3
*/ SJF CPU Scheduling Algorithm (Non-Preemptive)
//PROGRAM FOR SHORTEST-JOB-FIRST(SJF) "CPU SCHEDULING ALGORITHM" WITHOUT PRE_EMPTION
#include<stdio.h>
#include<conio.h>
int main()
{
int at[10], bt[10], ct[10], wt[10], ta[10], tat[10];
//at-ArritvalTime::br-BurstTime::ct-CompletionTime::ta-TemporaryArray
//wt-WaitingTime::tat-TurnAroundTime::tn-CurrentTime(TimeNow)
int n, i, k, pc=0, pointer = 0, tn =0, c;//pc-ProcessesCompleted
char pn[10][10]; //pn-ProcessName
printf("Enter the number of processes: ");
scanf("%d",&n);
printf("Enter <ProcessName> <ArrivalTime> <BurstTime>\n");
for(i=0;i<n;i++)
scanf("%s%d%d",&pn[i],&at[i],&bt[i]);
for(i=0; i<n; i++)
{
ct[i] = -1;
ta[i] = bt[i];
}
while(pc!=n)
{
c = 0;
for(i=0; i<n; i++)
if(ct[i]<0 && at[i]<=tn)
c++;
if(c==0)
tn++;
else
{
pointer = 0;
while(at[pointer]>tn || ct[pointer]>0)
pointer++;
for(k=pointer+1; k<n; k++)
if(at[k]<=tn && ct[k]<0 && bt[pointer]>bt[k])
pointer = k;
if(ct[pointer]<0)
{
tn=tn+bt[pointer];
bt[pointer] = 0;
ct[pointer] = tn;
wt[pointer] = ct[pointer] - ( at[pointer]+ ta[pointer] );
tat[pointer] = ct[pointer] - at[pointer];
pc++;
}
}
}
printf("\nPN\tAT\tBT\tCT\tWT\tTAT\n");
for(i=0;i<n;i++)
printf("%s\t%d\t%d\t%d\t%d\t%d\n",pn[i],at[i],ta[i],ct[i],wt[i],tat[i]);
return 0;
}
/* EXAMPLE OUTPUT
Enter the number of processes: 6
Enter <ProcessName> <ArrivalTime> <BurstTime>
p1 3 2
p2 6 5
p3 1 1
p4 6 2
p5 15 3
p6 20 10
PN AT BT CT WT TAT
p1 3 2 5 0 2
p2 6 5 13 2 7
p3 1 1 2 0 1
p4 6 2 8 0 2
p5 15 3 18 0 3
p6 20 10 30 0 10
*/
//ANOTHER PROGRAM for the same problem
//PROGRAM FOR SHORTEST-JOB-FIRST(SJF) "CPU SCHEDULING ALGORITHM" WITH NO-PRE_EMPTION & ARRIVAL TIMES
#include<stdio.h>
#include<string.h>
int main(void)
{
//VARIABLE DECLARATION
char pn[20][20], c[20][20]; //PN-PROGRAM NAMES C-A TEMPORARY ARRAY
int n,i,j,at[20], bt[20], wt[20],ct[20],tat[20]; //bt-BURST TIME ; wt-WAITING TIME; tat-TURN AROUND TIME
int temp1, temp2, count=0,twt=0;//,tat=0;
printf("Enter number of processes:");
scanf("%d", &n);
printf("Enter PN, AT, BT:\n");
//TAKING INPUT VALUES i.e., PROCESS-NAMES, ARRIVAL-TIMES AND BURST-TIMES
for(i=0; i<n; i++)
scanf("%s%d%d",&pn[i],&at[i],&bt[i]);
//SCHEDULING THE PROCESSES ACCORDING TO SJF
for(i=0 ; i<n; i++)
{
for(j=i+1; j<n; j++)
if (
//IF THERE IS NO PROCESS IN MAIN MEMORY,
//SORT PROCESSES ACCORDING TO ARRIVAL TIMES &
//IF WE GOT PROCESSES WITH SAME ARRIVAL TIME SORT THEM BY BURST TIMES
( (i==0||count<1)&&(at[i]>at[j]||(at[i]==at[j]&&bt[i]>bt[j])) )
//IF WE GOT ONLY ONE PROCESS IN MAIN MEMORY AFTER COMPLETION OF THE CURRENT PROCESS
|| (count == 1 && ct[i-1]>=at[j])
//IF WE GOT MORE THAN ONE PROCESS IN MAIN MEMORY, SORT THEM BY BURST TIMES
|| ((ct[i-1]>=at[j]&&bt[i]>bt[j]))// || (ct[i-1]<at[i]&&ct[i-1]>=at[j]))
)
//SWAPPING PROCESSES
{
temp1 = bt[i];
temp2 = at[i];
bt[i] = bt[j];
at[i] = at[j];
bt[j] = temp1;
at[j] = temp2;
strcpy(c[i],pn[i]);
strcpy(pn[i],pn[j]);
strcpy(pn[j],c[i]);
}
if(i==0 || count<1)
ct[i] = at[i] + bt[i];
else
ct[i] = ct[i-1] + bt[i];
wt[i] = ct[i] - (at[i] + bt[i]);
tat[i] = ct[i] - at[i];
count = 0 ;
for(j=i+1; j<n; j++)
if(ct[i]>=at[j])
count++;
}
//PRINTING THE VALUES AFTER ALL PREOCESSES COMPLETED
printf("S.N.\tProcess-Name\tArrival-Time\tBurst-Time\tCT\tWT\tTAT\n");
for(i=0; i<n; i++)
printf("%d\t\t%s\t\t%d\t\t%d\t%d\t%d\t%d\n",(i+1),pn[i],at[i],bt[i],ct[i],wt[i],tat[i]);
} //END OF MAIN
/* EXAMPLE OUTPUT
Enter number of processes:6
Enter PN, AT, BT:
p1 3 2
p2 6 5
p3 1 1
p4 6 2
p5 15 3
p6 20 10
S.N. Process-Name Arrival-Time Burst-Time CT WT TAT
1 p3 1 1 2 0 1
2 p1 3 2 5 0 2
3 p4 6 2 8 0 2
4 p2 6 5 13 2 7
5 p5 15 3 18 0 3
6 p6 20 10 30 0 10
*/
FCFS
FCFS CPU Scheduling Algorithm
//PROGRAM FOR FIRST-COME-FIRST-SERVE "CPU SCHEDULING ALGORITHM"
#include<stdio.h>
#include<string.h>
int main(void)
{
//VARIABLE DECLARATION
char pn[20][20], c[20][20]; //PN-PROGRAM NAMES
int n,i,j,at[20], bt[20], wt[20],tat[20], ct[20]; //bt-BURST TIME ; wt-WAITING TIME; tat-TURN AROUND TIME
int twt=0, ttat=0, temp1, temp2;
printf("Enter number of processes:");
scanf("%d", &n);
//TAKING INPUT VALUES i.e., PROCESS-NAMES, ARRIVAL-TIMES AND BURST-TIMES
printf("Enter <Process-name> <Arrival-time> <Burst-time> for processes:\n", (i+1));
for(i=0; i<n; i++)
scanf("%s%d%d",&pn[i],&at[i],&bt[i]);
//SORT THE PROCESSES ACCORDING TO ARRIVAL TIMES
for(i=0;i<n;i++)
{
for(j=i+1; j<n;j++)
{
if(at[i]>at[j])
{
temp1 = bt[i];
temp2 = at[i];
bt[i] = bt[j];
at[i] = at[j];
bt[j] = temp1;
at[j] = temp2;
strcpy(c[i],pn[i]);
strcpy(pn[i],pn[j]);
strcpy(pn[j],c[i]);
}
}
if(i==0) ct[0]=at[0]+bt[0];
if(i>0)
{
if(at[i]>ct[i-1])
ct[i]=at[i]+bt[i];
else
ct[i]=ct[i-1]+bt[i];
}
}
//CALCULATING WAITING TIME & TAT
wt[0]=0;
tat[0]=ct[0]-at[0];
for(i=1;i<n;i++)
{
tat[i] = ct[i]-at[i];
wt[i] = tat[i]-bt[i];
twt += wt[i];
ttat += tat[i];
}
//PRINTING THE VALUES AFTER ALL PREOCESSES COMPLETED
printf("S.N.\tPN\tAT\tBT\tCT\tWT\tTAT\n");
for(i=0; i<n; i++)
printf("%d\t%s\t%d\t%d\t%d\t%d\t%d\n",(i+1),pn[i],at[i],bt[i],ct[i],wt[i],tat[i]);
printf("Total waiting time:%d\n", twt);
printf("Total Turn Around Time:%d", ttat);
}
Friday, 1 April 2016
CCNA
Cisco’s Networking Academy offers you the skills and knowledge
required for home and small business networking. After completing this
course you will have the opportunity to sit for the newly revised
CCNA-ENT (Cisco Certified Network Associate, Entry-level Network
Technician) industry exam.
You are asking for the CCNA Course syllabus. Here I am uploading a file that contains the CCNA Course syllabus. This is as follows:
Class Expectations
Enter Prepared
Use Technology Responsibly
Behave Maturely
Lab Policies
Leave Things As You Found Them (or Better)
Maintain Privacy, Security, and Independence
Leave Food and Drink Outside
You can download CCNA Course syllabus from here. This is as follows:
CCNA Course syllabus
CCNA Course E-book
in a pdf atteched for more detail..............
You are asking for the CCNA Course syllabus. Here I am uploading a file that contains the CCNA Course syllabus. This is as follows:
Class Expectations
Enter Prepared
Use Technology Responsibly
Behave Maturely
Lab Policies
Leave Things As You Found Them (or Better)
Maintain Privacy, Security, and Independence
Leave Food and Drink Outside
You can download CCNA Course syllabus from here. This is as follows:
CCNA Course syllabus
CCNA Course E-book
in a pdf atteched for more detail..............
Cisco
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